(125/x^2-5x)+5=25/x-5

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Solution for (125/x^2-5x)+5=25/x-5 equation: 



(125/x^2-5x)+5=25/x-5

We move all terms to the left:

(125/x^2-5x)+5-(25/x-5)=0



Domain of the equation: x^2-5x)!=0

x∈R





Domain of the equation: x-5)!=0

x∈R



We get rid of parentheses

125/x^2-5x-25/x+5+5=0

We calculate fractions

We do not support expression: x^3

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